What are the coordinates of the vertex of the graph of the function y = –x² + 6x –11?

(3, –2)

(3, 16)

(–3, –29)

(–3, –20)

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Verified Answer :

bcalle bcalle · Answer 1 · 2016-11-27T15:39:10-05:00

The answer is (3,-2)

Use x=-b/2a to get the x value then substitute that number back into the equation to get y.
x=-6/-2 = 3
-(3)^2+6(3)-11 =-2

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ApusApus ApusApus · Answer 2 · 2019-09-23T11:18:53-04:00

Answer:

A. \((3,-2)\)

Step-by-step explanation:

We have been given a function formula \(y=-x^2+6x-11\). We are asked to find the coordinates of the vertex of the graph.

We know that the x-coordinate of an equation in form \(y=ax^2+bx+c\) can be determined using formula \(\frac{-b}{2a}\).

We can see that value of b is 6 and value of a is -1.

\(\frac{-6}{2(-1)}\)

\(\frac{-6}{-2}\)

\(3\)

Now, we will substitute \(x=3\) in given formula to find y-coordinate.

\(y=-(3)^2+6(3)-11\)

\(y=-9+18-11\)

\(y=-2\)

Therefore, the coordinates of vertex of the given function are \((3,-2)\).