The answer is 3/125
\(log_a(x) - log_a(y)=log_a( \frac{x}{y} ) \\
log_5(3) - log_5(5x) = log_5( \frac{3}{5x})\)
\(log_5( \frac{3}{5x})=2\)
Since \(log_b(x)=y\) is \(b^{y} =x\), then:
\(log_5( \frac{3}{5x})=2\) is
\(5^{2} = \frac{3}{5x} \\ 25 = \frac{3}{5x} \\ 5x*25=3 \\ 125x=3 \\ x=3/125\)
