A gas has a pressure of 120 kpa, a temperature of 400 k and a volume of 50 milliliters. what volume will the gas have at a pressure of 60 kpa and a temperature of 200 kpa?
We use the ideal gas relationship,
PV/T = constant
P₁V₁/T₁ = P₂V₂/T₂
120 x 50 / 400 = 60 x V₂ / 200
V₂ = 50 ml
The new volume of the gas as pressure and temperature are decreased to the given values is 50mL.
Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.
It is expressed as;
P₁V₁/T₁ = P₂V₂/T₂
Given the data in the question;
P₁V₁/T₁ = P₂V₂/T₂
P₁V₁T₂ = P₂V₂T₁
V₂ = P₁V₁T₂ / P₂T₁
V₂ = ( 120kPa × 50mL × 200K ) / (60kPa × 400K )
V₂ = 1200000 mLkPaK / 24000kPaK
V₂ = 50mL
The new volume of the gas as pressure and temperature are decreased to the given values remains at 50mL.
Learn more about the combined gas law here: brainly.com/question/25944795
#SPJ5