According to the fundamental theorem of algebra, how many zeros does the polynomial below have?

f(x)=x^5-12x^3+7x-5

Step-by-step explanation: We are given to find the number of zeroes of the following polynomial according to the fundamental theorem of algebra.

\(f(x)=x^5-12x^3+7x-5.\)

Fundamental theorem of algebra: According to this theorem, a polynomial with degree n has n zeroes.

Now, the degree of the given polynomial is 5, since the highest power of the unknown variable is 5.

Therefore, according to fundamental theorem of algebra, the number of zeroes of the given polynomial f(x) is 5.

Thus, the required number of zeroes is 5.

According to the fundamental theorem of algebra, how many zeros does the polynomial below have?f(x)=x^5-12x^3+7x-5

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According to the fundamental theorem of algebra, how many zeros does the polynomial below have?

f(x)=x^5-12x^3+7x-5