The answer is 5/2
\(log_x(y) = \frac{log(y)}{log(x)} \\ log_4(32) = \frac{log(32)}{log(4)}\)
\(log (x^{a}) =a*log(x) \\ log(32)= log( 2^{5})=5*log(2) \\
log(4)= log( 2^{2})=2*log(2)\)
\(\frac{log(32)}{log(4)}= \frac{5*log(2)}{2*log(2)} = \frac{5}{2}\)
