Verified Answer :

- subtract 3rd from second

 
2x +3y -3z = -6

2x +2y -z = 0

---------------

 0 y -2z = -6

 
- multiply first by -2 and assum by second

 
-2x -2y +8z = 14

  2x +3y -3z = -6

----------------

  0 y +5z = 8

 
y-2z=-6

y+5z=8

---------- subtract second from first

 0 -7z =-14

z=2

 
y+5z=8

y+5*2=8

y+10=8

y=-2

 
z=2

y=-2

 
x+y -4z=-7

x +(-2) -4(2) = -7

x-2-8=-7
x-10=-7

x=3

 
x=3

y=-2

z=2

andrestorres226

Answer:

Step-by-step explanation:

- subtract 3rd from second

2x +3y -3z = -6

2x +2y -z = 0

---------------

0 y -2z = -6

 - multiply first by -2 and assum by second

-2x -2y +8z = 14

 2x +3y -3z = -6

----------------

 0 y +5z = 8

y-2z=-6

y+5z=8

---------- subtract second from first

0 -7z =-14

z=2

y+5z=8

y+5*2=8

y+10=8

y=-2

z=2

y=-2

 x+y -4z=-7

x +(-2) -4(2) = -7

x-2-8=-7

x-10=-7

x=3

x=3

y=-2

z=2

Related Questions