*ABCD is a rhombus with diagonals intersecting at E. If m<ABC = 4m<BAD, find m<EBC.
Well, your question is a bit incomplete that makes it worse to give you exactly what you need. But, according to the fact that diagonals intersecting, all the angles =360 degrees.
Suppose \(\ \textless \ BAD=x\). and \(\ \textless \ ABC=4x\)
which means that opposite ones are equal
so, the solution is :
\(2(x+4x)=360\)
or could be \(10x= 360
x=36\)
So, we have : <BAD=36 and <ABC=144
And the answer is : 4m+m=180.
Do hope you will find it helpful!
