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A customer sits in an amusement park ride in which the compartment is to be pulled downwards in the negative direction of y axis with accelaration magnitude of 1.24 g(g=9.8 m/sec ^2). A 0.567 gms coin is placed on customers knee. once motion begins,

find coins accelaration relative to

a)ground

b)customer

Chow long does the coin take to reach the compartment ceiling 2.2 m above the knee.

d)the actual force on the coin

e)the apparent force according to customer's measure of coins accelaration

Verified Answer :

Edufirst

This movement of the coin relative to the knee is not under an inertial frame, because knee is accelerated relative to the coin.

a) coin acceleration relative to the ground: g = 9.81 m/s^2. This is the acceleration due to the atraction of the earth, given that the coin is not tied to the car or to the knee.

b) coin acceleration relative to the knee: acceleration of the coin relative to the ground - acceleration of the knee relative to the ground = - g - (-1.24g) = 0.24 g = 0.24 9.81 m^2^2 = 2.354 m/s^2

c) time to the coin move 2.2 m upward, relative to the car

d =  at^2 / 2 , where a is the acceleration relative to the car (same of the knee)

=> t = √(2d/a) = √(22.2m/2.354 m/s^2) = 1.37 s

d) actual force on the coin

Use the acceleration relative to the ground, a=g = 9.81 m/s^2

F = ma = 0.567 g 10^-3 kg/g 9.81 m/s^2 = 5.5610^-3 N


e) apparent force

Use apparent acceleration, a = 2.354 m/s^2

F = ma = 0.56710^-3 kg 2.354 m/s^2 = 1.33*10^-3 N

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