The inequality would look like this:
-2 (3x + 2)\(\geq\)-6x-4
To begin to find the solutions, distribute the -2 throughout the set of parenthesis on the left side of the inequality by multiplying the -2 by each term in the set of parenthesis
-2 x 3x = -6x
-2 x 2 = -4
-6x -4 \(\geq\)-6x-4
Begin to isolate x by performing the opposite operation of adding -6x on both sides of the inequality
0x -4 \(\geq\)-4
Next perform the opposite operation by adding 4 on both sides of the inequality
0x \(\geq\) 0
Now, I'm not exactly understanding how that can possibly work. So, I guess I didn't really help you. But add a comment so that we can talk about the problem :)
