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Ammonia and gaseous hydrogen chloride combine to form ammonium chloride. NH3+HCL->NH4CL


if 4.21 L of NH3(g) at 27 C and 1.02 atm is combined with 5.35 L of HCL(g) at 26 C and 0.998 atm what mass of NH4Cl(s) will be produced? which gas is the limiting reactant? which gas is present in excess?

Verified Answer :

MissPhiladelphia

The balanced chemical equation would be as follows:

NH3+HCL->NH4CL

For this, we assume these gases are ideal gases so we can use the equation PV=nRT. We first calculate the number of moles of each reactants. We do as follows:

PV=nRT
1.02 (4.21) = n (0.08206)(27+273.15)
n = 0.17 mol NH3 ------->consumed completely and therefore the limiting reactant

PV=nRT
0.998 (5.35 L) = n (0.08206)(26+273.15) 
n = 0.22 mol HCl

what mass of NH4Cl(s) will be produced?
0.17 mol NH3 (1 mol NH4Cl / 1 mol NH3 ) = 0.17 mol NH3

which gas is the limiting reactant?
 NH3 gas

which gas is present in excess?
HCl gas

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