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Verified Answer :

MissPhiladelphia

The given equation is:

\(\frac{q+5}{-3} * \frac{-3q}{q+2}\)

Just multiply both numerators and both denominators respectively, with the bar line still between them. So, it becomes

\(\frac{(q+5)(-3q)}{(-3)(q+2)} = \frac{-3 q^{2}-15q }{-3q-6}\)

Then you factor out the equations:

\(\frac{-3 q^{2}-15q }{-3q-6} = \frac{-3q(q+5)}{-3(q+2)}\)

Simplify terms by dividing them. The negative sign and 3 cancels out. The answer would be:

\(\frac{q(q+5)}{(q+2)}\)

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