Let a_n be the n th digit after the decimal point in

9pi+5e. Evaluate the sum n=1 to infinity of a_n(.1)^n.

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25-11-2016
Mathematics

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Let a_n be the n th digit after the decimal point in

9pi+5e. Evaluate the sum n=1 to infinity of a_n(.1)^n.

Verified Answer :

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Anonymous Anonymous · Answer 1 · 2016-11-27T05:31:20-05:00

I believe this should just be equal to
9π+5e−(⌊9π+5e⌋)=9π+5e−41
The first element in your sum should be the first digit after the decimal point times .1, so you have
.8
The next element in the sum is the second digit after the decimal place times .01, so you get
.8+.06=.86

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Let a_n be the n th digit after the decimal point in9pi+5e. Evaluate the sum n=1 to infinity of a_n(.1)^n.

Verified Answer :

Related Questions

Let a_n be the n th digit after the decimal point in

9pi+5e. Evaluate the sum n=1 to infinity of a_n(.1)^n.