Answer:
v = 9.43 m/s
Explanation:
According to Hooke's law;
F = kx ------------- eqn 1
where F = spring force = 80 N
k = spring constant = ?
x = spring stretch = 0.200 m
substitute for F and x to find k
80 = 0.2k
\(k = \frac{80}{0.2} = 400 N/m\)
\(\frac{1}{2} kx^{2} = \frac{1}{2} mv^{2}\)
\(\frac{1}{2}X400X0.2^{2} = \frac{1}{2}X 0.18v^{2}\)
\(200 X 0.04 = 0.09v^2\)
\(8 = 0.09v^2\)
\(v^2 = \frac{8}{0.09}\)
\(v^2 = 88.89\)
\(v = \sqrt{88.89}\)
\(v = 9.43m/s\)
