In this exercise we have to use the knowledge of implicit derivative to calculate the value of the given equation:
\(dX/dt = (X - 1)(1 - 2X)\)
To start the exercise we have to remember how to do an implicit derivation, so:
The implicit derivation is a method that allows us to find the derivative of a function that is only shown implicitly to us, like this y=f(x). In this case, we don't have exactly the function, but a relation that mixes x with y.
First, we have that the equation is given by:
\(ln[(2X - 1)/(X - 1)] = t\\(2X - 1)/(X - 1) = e^t\\2X - 1 = (X - 1)*e^t\\2X - X*e^t = 1 - e^t \\X*(2 - e^t) = 1 - e^t \\X = (1 - e^t)/(2 - e^t) = (e^t - 1)/(e^t - 2)\)
Now using the same equation and differentiating it, we find that:
\(ln[(2X - 1)/(X - 1)] = ln(2X - 1) - ln(X - 1) = t \\(2/(2X - 1))*dX/dt - (1/(X - 1))*dX/dt = 1\\dX/dt*((2*(X - 1) - (2X - 1)) / ((2X - 1)(X - 1))) = 1 \\dX/dt*(-1) = (2X - 1)(X - 1) \\dX/dt = (X - 1)(1 - 2X)\)
See more about implicit derivate at brainly.com/question/24516698