What is the number of moles in 0.025 g (NH4)2Cr2O7?
We are asked to calculate the number of moles in a given mass of a substance. To be able to calculate it, we need the molar mass of the substance. For (NH4)2Cr2O7, the molar mass would be 252.07 g/mol. We calculate as follows:
0.025 g (NH4)2Cr2O7 ( 1 mol / 252.07 g ) = 0.0001 mol (NH4)2Cr2O7
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Moles can be defined as the mass of a compound with respect to molar mass. The moles of \(\rm (NH_4)_2Cr_2O_7\) are \(\rm \bold{9.91\;\times\;10^{-5}}\).
The molecular mass of the compounds is the mass of each element in the formula unit.
The molecular mass of \(\rm (NH_4)_2Cr_2O_7\) is 252.06 g/mol.
The moles of the compound can be given as:
\(\rm Moles=\dfrac{Mass}{Molar\;mass}\)
The mass of \(\rm (NH_4)_2Cr_2O_7\) given is 0.025 g. The moles of \(\rm (NH_4)_2Cr_2O_7\) are:
\(\rm Moles=\dfrac{0.025\;g}{252.06\;g/mol} \\Moles=9.91\;\times\;10^{-5}\;mol\)
The moles of \(\rm (NH_4)_2Cr_2O_7\) in 0.025-gram sample are \(\rm \bold{9.91\;\times\;10^{-5}}\).
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