Web Analytics

Verified Answer :

To solve for the 7th term of a geometric sequence with t1 = 6 and r = 4, we use the following equation:




a(n) = a(1) r^(n-1)

a7 = (6) 4^(7-1)
a7 = 24576

Hope this answers the question. Have a nice day. Feel free to ask more questions.

Answer:

24,576.

Step-by-step explanation:

We have been given that first term of a geometric sequence is 6 and common ratio is 4. We are asked to find the 7th term of the sequence.

We know that a geometric sequence is in form \(a_n=a_1\cdot r^{n-1}\), where,

\(a_n\) = nth term of sequence,

\(a_1\) = 1st term of sequence,

\(r\) = common ratio.

Upon substituting \(a_1=6\) and \(r=4\) and \(n=7\) in geometric sequence formula, we will get:

\(a_7=6\cdot(4)^{7-1}\)

\(a_7=6\cdot(4)^{6}\)

\(a_7=6\cdot 4,096\)

\(a_7=24,576\)

Therefore, the 7th term of the given geometric sequence would be 24,576.