Answer: The compounds having same empirical formula are \(C_7H_{14}\text{ and }C_{10}H_{20}\)
Explanation:
Empirical formula is defined as the formula in which atoms in a compound are present in simplest whole number ratios. The atoms in the compounds must be same.
For the given options:
- Option A: \(NO\text{ and }NO_2\)
Empirical formula of NO = NO
Empirical formula of \(NO_2=NO_2\)
Thus, they do not have the same empirical formula
- Option B: \(C_4H_{10}\text{ and }C_{10}H_4\)
Empirical formula of \(C_4H_{10}=C_2H_5\)
Empirical formula of \(C_{10}H_4=C_5H_2\)
Thus, they do not have the same empirical formula
- Option C: \(CO_2\text{ and }SO_2\)
Empirical formula of \(CO_2=CO_2\)
Empirical formula of \(SO_2=SO_2\)
Thus, they do not have the same empirical formula
- Option D: \(C_6H_{12}\text{ and }C_{6}H_{14}\)
Empirical formula of \(C_6H_{12}=CH_2\)
Empirical formula of \(C_{6}H_{14}=C_3H_7\)
Thus, they do not have the same empirical formula
- Option E: \(C_7H_{14}\text{ and }C_{10}H_{20}\)
Empirical formula of \(C_7H_{14}=CH_2\)
Empirical formula of \(C_{10}H_{20}=CH_2\)
Thus, they have the same empirical formula
Hence, the compounds having same empirical formula are \(C_7H_{14}\text{ and }C_{10}H_{20}\)