If 5.7 moles of zinc metal react with 8.9 moles of silver nitrate, how many moles of silver metal can be formed, and how many moles of the excess reactant will be left over when the reaction is complete? Unbalanced equation: Zn + AgNO3 → Zn(NO3)2 + Ag Be sure to show all of your work.

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kmy2maryarde kmy2maryarde

25-11-2016
Mathematics

Answered

If 5.7 moles of zinc metal react with 8.9 moles of silver nitrate, how many moles of silver metal can be formed, and how many moles of the excess reactant will be left over when the reaction is complete? Unbalanced equation: Zn + AgNO3 → Zn(NO3)2 + Ag Be sure to show all of your work.

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Anonymous Anonymous · Answer 1 · 2016-11-27T20:32:17-05:00

the balanced equation is

Zn + 2 AgNO3 = Zn(NO3)2 + 2 Ag

the ratio between Zn and AgNO3 is 1 : 2

moles AgNO3 required = 5.7 x 2 =11.4

we have only 8.9 moles of AgNO3 so it is the limiting reactant

moles Zn needed = 8.9/2=4.45

moles Zn in excess = 5.7 - 4.45 =1.25 ( or 1.3 at two significant figures)

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