Just solve this equation:
\(\displaystyle 5x^2+3x-2=0\\\\x_{1,2}= \frac{-3\pm \sqrt{9+40} }{10}= \frac{-3\pm \sqrt{49} }{10} = \frac{-3\pm7}{10}=(-1), \frac{2}{5}\)
So, solutions are equal to:
\(\displaystyle x_1= \frac{-3+ \sqrt{49} }{10} \\\\x_2= \frac{-3- \sqrt{49} }{10}\)
