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a football is kicked vertically upward from a height of 2 feet with an initial speed of 70 feet per seconds.

formula h=2+70t-16t(squared)

describe the balls height above ground (h) in feet(t)seconds ater kicked use the formula to find the balls height 3 seconds after it was kicked


the balls height 3 seconds after kicked was ? feet

Verified Answer :

syed514

All you need to do is plug in 3 for t:h=2+70(3)−16(3^2)
and the final answer is 68.

jhonlopera05

Answer:

Height after 3 seconds is 68 ft

Explanation:

Using the given equation

\(h=2+70t-16t^2\),

and replacing \(t=3\) in it

\(h=2+70(3)-16(3)^2\)

\(h=68 ft\)

The ball height 3 seconds after kicked it is 68 ft

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