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Answer:

Moles of magnesium present is 0.0833 moles

Explanation:

Magnesium reacts with oxygen to form magnesium oxide.

\(2Mg + O_2 \rightarrow 2MgO\)

Amount of magnesium = 2 g

Molar mass of magnesium = 24 g/mol

No. of moles of magnesium \(=\frac{2}{24} = 0.0833\ mol\)

So, moles of magnesium present is 0.0833 moles

onyebuchinnaji

The number of moles of magnesium present in the reaction is 0.083 mole.

The given parameters;

  • mass of magnesium, = 2 g
  • mass of magnesium oxide formed = 3.33 g

The chemical reaction of the given elements is written as;

\(2Mg \ \ + \ \ O_2 \ \ ---> \ \ 2MgO\)

From the reaction above;

2(24) -------------------------- 2 moles of magnesium

2 -------------------------------- ?

\(no\ of \ moles = \frac{2\times 2}{2(24)} = 0.083 \ mole\)

Thus, the number of moles of magnesium present in the reaction is 0.083 mole.

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