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Solve the inequality for x, assuming that a, b, and c are positive constants.

Aa(bx − c) ≥ bc

(Choose the correct answer)

1.[0, c/a]

  1. (c/b, bc/a)
  2. [c/a + c/b, infinity)
  3. (bc, a(b-c)/bc]
  4. (-infinity, c/b]

Verified Answer :

Nirina7

a(bx − c) ≥ bc, implies (bx − c) ≥ bc /a  and then  bx  ≥ bc/a + c, x≥ c/a +c/b
so the solution is 3. [c/a + c/b, infinity)

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