the easier way to solve this is to make a formula that will calculate number of cents miner earns at day "n"
observing given numbers we can conclude that the formula is:
1 2^n
we can see from numbers that they grow very fast which means that the earning/time function is exponential.
sum of first n days is:
a) 7 days
S = 1 (1-2^7)/(1-2) = 127
b) 14 days
S = 1(1-2^14)/(1-2) = 16383
c) 1 month
will probably get a number with lots of digits
S = 1(1-2^30)/(1-2) = 1073741824