\(1.
\\A_{\triangle{QDE}}= \frac{15\times15\times\sin{72^o}}{2} \approx 107
\\
\\A_{sector}= \frac{15^2\pi\times 72^o}{360^o } \approx 141.37
\\
\\A=141.37-107=34.37
\\
\\2.
\\C=2\times 15 \times \pi=30\pi
\\
\\3.
\\A=15^2\pi=225\pi
\\
\\4.
\\l= \frac{2\times 15 \pi \times 72^o}{360^o} =6\pi
\\
\\5.
\\A_{DQ}= \frac{15^2\pi}{2} = \frac{225\pi}{2}\)
