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Answer:

The value of y is 125 when x=25.

Step-by-step explanation:

It is given that y varies directly as x. It means y is proportional to x.

\(y\propto x\)

\(y=kx\)

Where k is constant of proportionality.

It is given that y=25 when x=5. Put x=5 and y=25 in the above equation to find the value of k.

\(25=k(5)\)

Divide both sides by 5.

\(5=k\)

The value of k is 5.

The relation between x and y is defined by the equation

\(y=5x\)

Put x=25 in the above equation.

\(y=5(25)\)

\(y=125\)

Therefore the value of y is 125 when x=25.

Answer:  The required value of y is 125.

Step-by-step explanation:  Given that the variable y varies directly as x. Also, y = 25 when x = 5.

We are to find the value of y when x = 25.

Given that y varies directly as x.

So, we have

\(y\propto x\\\\\Rightarrow y=kx~~~~~~~~~~~\textup{[where k is the proportionality constant]}\)

When x = 5, y = 25, then we have

\(y=kx\\\\\Rightarrow 25=k\times5\\\\\Rightarrow k=\dfrac{25}{5}\\\\\Rightarrow k=5.\)

So,

\(y=kx\\\\\Rightarrow y=5x.\)

Now, when x = 25, then the value of y will be

\(y=5x=5\times25=125.\)

Thus, the required value of y is 125.

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