f(x)= 9-x^2, x ≥ 0. f^-1(x)=??
\(y=9-x^{2},\ x\ge0\)Reverse \(x\) and \(y\):\(x=9-y^{2},\ y\ge0\)Solve for \(y\):\(x=9-y^{2}\)\(\rightarrow y^{2}=9-x\)\(\rightarrow y=\sqrt{9-x}\) since \(y\ge0\)
