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Verified Answer :

garcialnatalia

2^x=33
log2^x=log33
xlog2=log33
(xlog2)/log2 = (log33)/log2
x=(log33)/log2= 5.04439411936

apologiabiology

hmm, ok

so rememeber
\(log_ab=c\) means \(a^c=b\)
therefor

\(a^c=b\) is to \(2^x=33\)
as is
\(log_ab=c\) is to \(log_233=x\)

x=\(log_233\) or aprox 5.04439

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