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yoitsmiah
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A cyclist going downhill is accelerating at 1.2 m/s2. If the final velocity of the cyclist is 16 m/s after 10 seconds, what is the cyclist’s initial velocity?

Verified Answer :

bartdrinksmalk

Change in velocity (\(\Delta v\)) is acceleration (\(a\)) times time (\(t\))

Acceleration \(a=1.2\ m/s^{2}\)
Time \(t=10\ s\)
So \(\Delta v=at=1.2\ m/s^{2}*10\ s=12\ m/s\)

The initial velocity is then \(16\ m/s-12\ m/s=4\ m/s\)

ajhabersham4

the answer to the problem is 4m/s

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