The volume of the hot tub is that of a cylinder:
\(V=\pi r^{2}h\)
The height is 1.5 m
The radius is half the diameter, which is 1.3 m
So we get
\(V=\pi(1.3)^{2}(1.5)\approx7.964 m^{3}\)
The density of water is 1 g/cm³
Convert to kg/m³:
\(\frac{1\ g}{1\ cm^{3}}*\frac{1\ kg}{1000\ g}*\frac{100^{3}\ cm^{3}}{1\ m^{3}}=\frac{10^{6}}{10^{3}}\ kg/m^{3}=1000\ kg/m^{3}\)
The mass of the water is Volume*density:
\(7.964\ m^{3}*1000\ kg/m^{3}=7964\ kg\)
So 7964 kg of water are needed to fill the tub.
