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Which product of prime polynomials is equivalent to 8x3 – 2x?

x(2x – 1)(2x – 1) 2x(x + 1)(x – 1) 2x2(2x + 1)(2x – 1) 2x(2x + 1)(2x – 1)

Verified Answer :

texaschic101

2x(2x + 1)(2x - 1) =
2x(4x^2 - 1) =
8x^3 - 2x

Answer:

  2x(2x+1)(2x-1)  

Step-by-step explanation:

We have been given the polynomial

\(8x^3-2x\)

We will take common factor out which is 2x

\(2x(4x^2-1)\)

Now, using\(a^2-b^2=(a+b)(a-b)\)

\(a=2x\text{and}b=1\)

\(4x^2-1=(2x-1)(2x+1)\)

So, given polynomial is equivalent to: 2x(2x+1)(2x-1)

Therefore, last option is correct.

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