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Verified Answer :

6.7× 10³ g/mol*L ×(1Kg÷1000g) × (1L÷10dL)=  0.67

Answer : The answer is, \(0.67\text{ Kg}/mole\text{ dL}\)

Step by step explanation :

For this problem the conversion factors used are,

\((1kg=1000g)\\\\(1L=10dL)\)

Convert \(6.7\times 10^3\text{ g}/mole\text{ L}\) to \(\text{ Kg}/mole\text{ dL}\) :

\(6.7\times 10^3\text{ g}/mole\text{ L}\\\\\Rightarrow \frac{6.7\times 10^3}{10^3}\text{ Kg}/mole\text{ L}\\\\\Rightarrow \frac{6.7}{10}\text{ Kg}/mole\text{ dL}\\\\\Rightarrow 0.67\text{ Kg}/mole\text{ dL}\)

Hence, the answer is, \(0.67\text{ Kg}/mole\text{ dL}\)

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