Answer:
The volume of the larger cube is 5.08 g/cm³.
Explanation:
Given that,
Mass of smaller cube = 20 g
Density of smaller cube \(\rho= 7.87 g/cm^2\)
Dylan has two cubes of iron.
The larger cube has twice the mass of the smaller cube.
\(M_{l}=2m_{s}\)
Density is same for both cubes because both cubes are same material.
The density is equal to the mass divided by the volume.
\(\rho=\dfrac{m}{V}\)
\(V=\dfrac{m}{\rho}\)
Where, V = volume
m = mass
\(\rho=density\)
We need to calculate the volume of smaller mass
The volume of smaller mass
\(V_{s}=\dfrac{m_{s}}{\rho_{s}}\)
\(V_{s}=\dfrac{20}{7.87}\)
\(V_{s}=2.54\ cm^3\)
Now, We need to calculate the volume of large cube
\(V_{l}=\dfrac{m_{l}}{\rho_{l}}\)
\(V_{l}=\dfrac{2\times20}{7.87}\)
\(V_{l}=5.08\ g/cm^3\)
Hence, The volume of the larger cube is 5.08 g/cm³.
