\(f(x)= \left \{ {{ \sqrt{x} } \atop {2x-1}} \right.
\\
\\ f'(x)= \left \{ {{ \frac{1}{2\sqrt{x}} } \atop {2}} \right.
\\
\\ f'(1)= \left \{ {{ \frac{1}{2}} \atop {2}} \right.
\\
\\ f'(1^-)
eq f'(1^+)\)
Therefore, the function is not differentiable at x = 1.
\(f(x)= \sqrt{x}
\\
\\f'(x)= \frac{1}{2 \sqrt{x} }
\\
\\f'(0)=\frac{1}{2 \sqrt{0} } = \infty\)
Therefore, the function is not differentiable at x = 0.
