Find the area of a circle whose area equals the half of the sum of the areas of two circles with radii 2 and 3.
Answer:
The area of a circle is 20.41 units.
Step-by-step explanation:
Formula
\(Area\ of\ a\ circle = \pi r^{2}\)
Where r is the radius of a circle.
As given
First take when the radius of a circle is 2 unit.
\(\pi = 3.14\)
radius = 2 units
Put in the formula
\(Area\ of\ a\ circle = 3.14\times 2\times 2\)
= 12.56 unit
Second take when the radius of a circle is 3 unit.
\(\pi = 3.14\)
radius = 3 units
Put in the formula
\(Area\ of\ a\ circle = 3.14\times 3\times 3\)
= 28.26 unit
As given
The area of a circle whose area equals the half of the sum of the areas of two circles with radii 2 and 3.
\(Area\ of\ a\ circle = \frac{Area\ of\ circle\ with\ radius\ 2units+Area\ of\ circle\ with\ radius\ 3units }{2}\)
Put the value in the above
\(Area\ of\ a\ circle = \frac{12.56 +28.26}{2}\)
\(Area\ of\ a\ circle = \frac{40.82}{2}\)
Area of a circle = 20.41 units
Therefore the area of a circle is 20.41 units.