If g(x) = 4x - 4^x, what is the value of g(3/2)?
\(g(x)=4x-4 ^{ x}\) \(g( \frac{3}{2})=4( \frac{3}{2})-4^{ (\frac{3}{2}) }\)\(g( \frac{3}{2})=6- \sqrt[2]{4^{3} }\)\(g( \frac{3}{2})=6- \sqrt{64}\)\(g( \frac{3}{2})=6-8\)\(g( \frac{3}{2})=-2\)
g(x) = 4x - 4^x
so
g(3/2) = 4(3/2) - 4^3/2
g(3/2) = 6 - 32
4^3/2 = -26
