Answer: \(A=3\dfrac{3}{4}\ ft^2\)
Step-by-step explanation:
Given: The dimensions of the wrapping paper :
\(1\text{ and}\dfrac{1}{4}\text{ feet }\text{ by 3 feet}\\\\\text{i.e }1+\dfrac{1}{4}\text{ feet }\text{ by 3 feet}\\\\\text{i.e }\dfrac{5}{4}\text{ feet }\text{ by 3 feet}\)
Now, we know that the area of a rectangle is given by :-
\(A=length*width\)
Now, the area of the wrapping paper is given by :-
\(A=\dfrac{5}{4}\times3=\dfrac{15}{4}=3\dfrac{3}{4}\ ft^2\)
