Answer:
The upper quartile median value is 40. Therefore second option is correct.
Step-by-step explanation:
Stem is first digit of a number and leaf is last digit of a number.
Stem 1 leaf 4 can be written as 14.
From the given table, the observations can be written as
\(16,18,23,25,26,34,37,37,40,41,46\)
Total number of observations is 11, which is an odd number.
\(median=\frac{n+1}{2}\text{th term}\)
\(median=\frac{11+1}{2}\text{th term}=6\text{th term}\)
Therefore median is 34.
We have 5 terms before 34 and 5 terms after 34.
\(Q_1=\frac{n+1}{4}\text{th term}=3\text{th term}\)
\(Q_1=23\)
\(Q_3=\frac{3(n+1)}{4}\text{th term}=9\text{th term}\)
\(Q_3=40\)
Q₃ is also known as upper quartile median value. Therefore second option is correct.
