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Answer:

Step-by-step explanation:

A+B \(\left[\begin{array}{ccc}3&-3\\10&4^{\frac{1}{2} \\10&-1\end{array}\right]\) 3A\(\left[\begin{array}{ccc}6&-9\\0&15\\21&-6\end{array}\right]\)

The value of A+B is \(\left(\begin{array}{ccc}3&-3\\10&4.5\\10&-1\end{array}\right)\) and the value of 3A is  \(\left(\begin{array}{ccc}6&-9\\0&15\\21&-6\end{array}\right)\) .

How to add two matrices?

To add two matrices, we have to add the element present in the same position in the respective matrices.

(A+B)ij= Aij + Bij

where i is the no. of row and j is the no. of column.

How to multiply a scalar by the matrix?

In order to multiply a scalar by the matrix, we have to multiply that scalar with every element of the matrix.

nA= nAij

Here given matrix is

A= \(\left(\begin{array}{ccc}2&-3\\0&5\\7&-2\end{array}\right)\)

and the other matrix is

B= \(\left(\begin{array}{ccc}1&0\\10&-1/2\\3&1\end{array}\right)\)

The sum of the matrix is A+B=  \(\left(\begin{array}{ccc}2&-3\\0&5\\7&-2\end{array}\right)\)+  \(\left(\begin{array}{ccc}1&0\\10&-1/2\\3&1\end{array}\right)\)

⇒ A+B =\(\left(\begin{array}{ccc}2+1&-3+0\\0+10&5+(-1/2)\\7+3&-2+1\end{array}\right)\)

⇒ A+B= \(\left(\begin{array}{ccc}3&-3\\10&4.5\\10&-1\end{array}\right)\)

the value of 3A= 3 \(\left(\begin{array}{ccc}2&-3\\0&5\\7&-2\end{array}\right)\)=  \(\left(\begin{array}{ccc}6&-9\\0&15\\21&-6\end{array}\right)\)

Therefore the value of A+B is \(\left(\begin{array}{ccc}3&-3\\10&4.5\\10&-1\end{array}\right)\) and the value of 3A is  \(\left(\begin{array}{ccc}6&-9\\0&15\\21&-6\end{array}\right)\) .

Learn more about the addition of matrices

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