In the 1950s, an experimental train, which had a mass of 2.50X10^4 kg, was powered across a level track by a jet engine that produced a thrust of 5.00X10^5 N for a distance of 509m.

AFind the work done on the train
BFind the change in Kinetic energy.
CFind the final kinetic energy of the train if it started from rest.
DFind the final speed of the train if there had been no fricion. ...?

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a) Work = force x distance = 5.0 x 10^5 x 509 = 2.54 x 10^8
b) no change in velocity, therefore KE = 0
c) KE = 31 J
d) v = 15 m/s

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jbiain jbiain · Answer 2 · 2020-01-24T11:50:18-05:00

Answer:

a. 2.545 10^8 J

b. 2.545 10^8 J

c. 2.545 10^8 J

d. 141.688 m/s

Explanation:

Data:

mass, m = 2.510^4 kg

Force, F = 5.0010^5 N

distance, d = 509 m

a. Work, W = Fd = 5.0010^5 N 509 m = 2.545 10^8 J

b. Change in kinetic energy, ΔKE = W = 2.545 10^8 J

c. Change in kinetic energy = final kinetic energy - initial kinetic energy

If the train started from rest, initial kinetic energy = 0

Then, final kinetic energy, KEf = ΔKE = 2.545 10^8 J

d. From the definition of kinetic energy we can get the final speed (vf) as follows:

KEf = (1/2)mvf^2

vf = √(KEf2/m)

vf = √(2.545 10^82/2.5*10^4 )

vf = 141.688 m/s