F = mx'' = -kx
=> x'' + (k/m)x = 0
=> x(t) has period T
T = 2π / sqrt k/m
f = 1/T= sqrt k/m/2π
f = sqrt k/m/2π = sqrt 229/3.5 /2π = 1.29 sec − 1
This is the frequency of a vehicle that has a steady acceleration of 5.00m/s^2, and when the vehicle's speed has reached 45.0m/s, its engines turn off, thus eliminating its acceleration but not its velocity.
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