The typical exponential function, y = ax, has asymptote and y-intercept .

A)y = 0; (0,a)

B)y = 0; (0,1)

C)y = a; (0,a)

D)y = a; (0,1) ...?

The typical exponential function, y = ax, has asymptote y = 0 and y-intercept (0,1). The correct option among all the options that are given in the question is the second option or option "B". The other choices are incorrect and can be easily negated. I hope that this is the answer that has actually come to your help.

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danielafalvarenga danielafalvarenga · Answer 2 · 2019-09-23T10:01:02-04:00

Answer: B) The typical exponential function, y = ax, has asymptote the x-axis and y-intercept x = 0.

Step-by-step explanation:

For the funcion \(y = a^x\), the asymptote is the value that the function would never assum, but gets really close. In this case, there is no value for y = 0, because\(y = a^x\\0 = a^x \\ln(0) = x.lna\\ln(0)\)is not defined! This way, asymptote is x-axis (y=0).

y-intercept ⇒ x=0, so

\(y=a^x\\y=a^0=1\)

This, way, the point (0,1)

alternative b

The typical exponential function, y = ax, has asymptote ________ and y-intercept ________.A)y = 0; (0,a) B)y = 0; (0,1) C)y = a; (0,a) D)y = a; (0,1) ...?

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Related Questions

The typical exponential function, y = ax, has asymptote and y-intercept .

A)y = 0; (0,a)

B)y = 0; (0,1)

C)y = a; (0,a)

D)y = a; (0,1) ...?