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Verified Answer :

let 9x^2-1 = y^2 
=> 18xdx = 2ydy 
=> ydy = 9xdx 

lower limit = sqrt(92/9 - 1) = sqrt(1) = 1 
upper limit = sqrt(9
4/9 - 1) = sqrt(3) 

Int. [sqrt(2)/3,2/3] 1/(x^5(sqrt(9x^2-1)) dx 

= Int. [sqrt(2)/3,2/3] xdx/(x^6(sqrt(9x^2-1)) 
= 81 Int. [1,sqrt(3)] ydy/((y^2+1)^3y) 
=81
Int. [1,sqrt(3)] dy/(y^2+1)^3 

y=tanz 
dy = sec^2z dz 

=81Int [pi/4,pi/3] cos^4(z) dz 
=81/4
int [pi/4,pi/3] (1+cos(2z))^2 dz 
=81/4 Int. [pi/4,pi/3] (1+2cos(2z)+cos^2(2z)) dz 

=81/4
(pi/3-pi/4) + 81/4(sin(2pi/3)-sin(pi/2)) + 81/8 (pi/3-pi/4) 
+ 81/32 (sin(-pi/3)-sin(pi)) 
=81(pi/48+pi/96+1/4
(sqrt(3)/2 - 1) - 1/32 sqrt(3)/2) 
=81/32
(pi+3sqrt(3)-8)