suppose sin u= x and u is between 0 and pi/2. what is sec u? ...?
The question should be accompanied with choices, below are the choices:
a) sqrt(1-x^2)
b) x/sqrt(1-x^2)
c) sqrt(1-x^2)/x
D) 1/sqrt(1-x^2)
The answer should be c) sqrt(1-x^2)/x .
cos u = sqrt (1 - sin^2 u) = sqrt(1 - x^2), and cot u = cos u / sin u.
The required value will vary Between [1,∞)
It is the branch of science that studies the relation between right-angled triangles.
if sin u = x and u varies from 0 to \(\frac{\pi }{2}\)
We know, Sec u = \(\frac{1}{cos u}\)
Then, for sec u or sec u varying from 0 to \(\frac{\pi }{2}\) value will be in between [1,∞)
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