Answer:
Option A, \(100 \\\)%
Explanation:
Let the allele for non freckled trait be represented by “f”
The allele for freckled trait be represented by “F”
Let us consider that freckled trait is dominant over the non – freckled trait.
The genotype for a non – freckled parent will be “ff”
The genotype for a homozygous freckled parent will be “FF”
When a cross is carried out between a non – freckled parent and a homozygous freckled parent , the following offsprings are produced –
f f
F Ff Ff
F Ff Ff
Thus, all the four offsprings have heterozygous genotype. Since we assumed that freckled trait is dominant over the non – freckled trait, all the offsprings would be freckled.
Thus, the probability of a child having freckles would be
\(\frac{4}{4} * 100\\= 100\\\)%
Thus, option A is correct.
