Answer:
\(h=16t^2\)
Step-by-step explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32 ft/s²
\(s=ut+\frac{1}{2}at^2\\\Rightarrow h=ut+\frac{1}{2}32\times t^2\\\Rightarrow h=ut+16t^2\)
Here, u = 0 so,
\(h=0t+16t^2\\\Rightarrow h=16t^2\)
The equation is \(h=16t^2\)
\(24=16t^2\\\Rightarrow t=\sqrt{\frac{24}{16}}\\\Rightarrow t=1.22\ s\)
Time taken by the ball to hit the ground is 1.22 seconds
