Web Analytics
Answered

The average life of a brand of automobile tires is 30,000 miles, with a standard deviation of 2,000 miles. If a tire is selected and tested, find the probability that it will have a lifetime between 25,000 and 31,000 miles. Assume the variable is normally distributed. Give your answer rounded to four decimal places (to the nearest ten-thousandth).

Verified Answer :

MissPhiladelphia

Find the z
scores for 25000 and 28000.

z1=( x –
average)/ standard deviation =( 25000-30000)/ 2000 = -2.5

z2=( x –
average)/ standard deviation =( 31000-30000)/ 2000 = 0.5

Find the
corresponding P(z).

 

P (z1) = 0.00621

P (z2) = 0.15866

Subtract the
probabilities to find the probability for the range,

(25000<= x
<=28000)

P(x) = 0.15866-0.00621
= 0.1524

Related Questions