A spinner used for a game is divided into 4 sections: Yellow, Brown, Red and Orange. The spinner is spun 50 times and lands on brown 18 times. What is the experimental probability that the spinner does NOT land on brown?
18/50 is the likelyness that it WILL land on brown, so that means that 32/50 chance that it WONT land on brown. Simplified it would be a 16/25 chance
or if you need to write it differently a 16:9 chance with 16 as will 9 as wont
Answer:
\(\frac{16}{25} =0.64\)
Step-by-step explanation:
Given : A spinner used for a game is divided into 4 sections: Yellow, Brown, Red and Orange. The spinner is spun 50 times and lands on brown 18 times
To Find: What is the experimental probability that the spinner does NOT land on brown
Solution :
Since we are given that the spinner is spun 50 times .
Ans the spinner lands on brown 18 times
Probability of landing on brown = \(\frac{18}{50} =\frac{9}{25}\)
Since we know that the sum of probabilities is 1
So, probability that the spinner does NOT land on brown is :
⇒ 1 - prob. of landing on brown
⇒\(1-\frac{9}{25}\)
⇒\(\frac{25-9}{25}\)
⇒\(\frac{16}{25}\)
Thus probability that the spinner does NOT land on brown is 16/25=0.64