The hypotenuse of a 45°-45°-90° triangle measures 128 cm.What is the length of one leg of the triangle?
64sqrt2 is the exact answer. 90.51 to the hundredth or 91 to the nearest whole.
The formula is hyp = sqrt2 times leg
Answer:
Since, a 45°-45°-90° triangle is a special type of isosceles right triangle, where the two legs are congruent to one another and the non-right angles are both equal to 45 degrees.
In 45°−45°−90° triangle
Sides are in the proportion \(1:1:\sqrt{2}\)
then,
the measures of the sides are \(x , x ,\sqrt{2}x\)
The length of hypotenuse= \(\sqrt{2}\) times the length of the leg. ....[1]
Given: length of hypotenuse = 128 cm.
then,
from [1] we have;
128 = \(\sqrt{2}\cdot x\)
or
\(x=\frac{128}{\sqrt{2}}\) = \(\frac{128}{\sqrt{2} } \times \frac{\sqrt{2}}{\sqrt{2}} = \frac{128\sqrt{2}}{\sqrt{2}\cdot \sqrt{2}}\)
Simplify:
\(x =\frac{128 \cdot \sqrt{2}}{2} =64\sqrt{2}\) cm.
Therefore, the length of one leg of the triangle is; \(64\sqrt{2}\) cm.