a0lexibertSehanna a0lexibertSehanna

21-11-2016
Mathematics

Answered

Give the excluded value(s) for the following fraction.

y+5/y^2+4y-32

Verified Answer :

antonsandiego antonsandiego

22-11-2016

Since we can divide by 0, we can clearly see that there is no way denominator can be 0. So, lets start :\(y^2+4y-32=0\).
The exluded values are lying in the y and we hav eto find them :\(y^2+4y-32=(y+8)*(y-4)=0\)
According to the info above,\(y+8=0 or y-4=0\)
y is -8 and 4.
That's all!

Answer Link

ethanpetersonxe ethanpetersonxe

01-01-2020

Answer:

y is -8 and 4.

Step-by-step explanation:

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