Let
x------> the biggest number
y------> the middle number
z------> the smallest number
we know that
\(x=2y\) -------> equation \(1\)
\(x+y=4z\) -------> equation \(2\)
\(z+y=x-2\) -------> equation \(3\)
substitute equation \(1\) in equation \(2\) and equation \(3\)
\([2y]+y=4z\) ------> \(3y=4z\) ------> equation \(4\)
\(z+y=[2y]-2\) ----> \(z+2=y\) ------> equation \(5\)
using a graph tool-----> to resolve the system of equations
see the attached figure
the solution is the point \((6,8)\)
\(z=6\\y=8\)
Find the value of x
\(x=2y\)
\(x=2*8=16\)
therefore
the answer is
the biggest number is \(16\)
the the middle number is \(8\)
the smallest number is \(6\)
